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9b^2+11b-4=0
a = 9; b = 11; c = -4;
Δ = b2-4ac
Δ = 112-4·9·(-4)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{265}}{2*9}=\frac{-11-\sqrt{265}}{18} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{265}}{2*9}=\frac{-11+\sqrt{265}}{18} $
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